Friday, December 20, 2019
Physics 2012 DSE - 2075 Words
Ã¥ ªÃ©â¢ éâ" ±Ã¥ ·Ã¥â ¡Ã¥ Æ'éâ" ± FOR MARKERSââ¬â¢ USE ONLY May 4, 2012 é ¦â¢Ã¦ ¸ ¯Ã¨â¬Æ'è © ¦Ã¥ Šè ©â¢Ã¦ ¸Ã¥ ±â¬ HONG KONG EXAMINATIONS AND ASSESSMENT AUTHORITY 2012 Ã¥ ¹ ´Ã© ¦â¢Ã¦ ¸ ¯Ã¤ ¸ Ã¥ ¸Ã¦â"â¡Ã¦â âèâ¬Æ'è © ¦ HONG KONG DIPLOMA OF SECONDARY EDUCATION EXAMINATION 2012 çⰠ©Ã§ â é ¦â¢Ã¦ ¸ ¯Ã¤ ¸ Ã¥ ¸Ã¦â"â¡Ã¦â âèâ¬Æ'è © ¦ è © ¦Ã¥ ·Ã¤ ¸â¬Ã¤ ¹â¢ PHYSICS HKDSE PAPER 1B æÅ" ¬Ã¨ ©â¢Ã¥ ·Ã¥ Æ'èâ¬Æ'ä ¹Æ'èâ¬Æ'è ©â¢Ã¥ ±â¬Ã¥ °Ëç⠺ä »Å Ã¥ ¹ ´Ã¦Å" ¬Ã§ §âèâ¬Æ'è © ¦Ã¨â¬Å'ç · ¨Ã¥ ¯ «Ã¯ ¼Å'ä ¾âºÃ©â" ±Ã¥ ·Ã¥â ¡Ã¥ Æ'èâ¬Æ' ä ¹â¹Ã§â ¨Ã£â¬âéâ" ±Ã¥ ·Ã¥â ¡Ã¥Å" ¨Ã¥ ®Å'Ã¦Ë Ã©â" ±Ã¥ ·Ã¥ · ¥Ã¤ ½Å"Ã¥ ¾Å'ï ¼Å'è⹠¥Ã¥ °â¡Ã¦Å" ¬Ã¨ ©â¢Ã¥ ·Ã¥ Æ'èâ¬Æ'æ ä ¾âºÃ¥â¦ ¶Ã¤ » »Ã¦â¢â¢ æÅ"Æ'èâ¬Æ'ç çšâæÅ" ¬Ã§ §âÃ¥ Å'ä ºâ¹Ã¥ Æ'éâ" ±Ã¯ ¼Å'æÅ" ¬Ã¥ ±â¬Ã¤ ¸ è ¡ ¨Ã¥ Ã¥ ° ï ¼Å'ä ½â é ËÃ¥Ëâ¡Ã¨ ¨Ëï ¼Å'Ã¥Å" ¨Ã¤ » »Ã¤ ½â¢Ã¦Æ'⦠æ ³ ä ¸â¹Ã¥ â¡Ã¤ ¸ Ã¥ ¾â"Ã¥ ® ¹Ã¨ ¨ ±Ã¦Å" ¬Ã¨ ©â¢Ã¥ ·Ã¥ Æ'èâ¬Æ'è ½Ã¥â¦ ¥Ã¥ ¸Ã§âŸæâ°â¹Ã¤ ¸ ãâ¬âÃ¥ ¸Ã§âŸè⹠¥Ã§ ´ ¢Ã©â" ±Ã¦Ëâ"æ ±âÃ¥ â" æ ¤Ã§ â°Ã¦â"â¡Ã¤ » ¶Ã¯ ¼Å'éâ" ±Ã¥ ·Ã¥â ¡/æâ¢â¢Ã¥ ¸ «Ã¦â¡â°Ã¥Å¡ ´Ã¨ ©Å¾Ã¦â¹âç µâ¢Ã¯ ¼Å'å⺠å ¸Ã§âŸæ ¥ µÃ¥ ¯Ã¨Æ' ½Ã¥ °â¡Ã¨ ©â¢Ã¥ ·Ã¥ Æ' èâ¬Æ'è ¦â"ç⠺æ ¨â¢Ã¦ ºâ"ç âæ ¡Ëï ¼Å'ä » ¥Ã¨â¡ ´Ã¤ ½â çŸ ¥Ã§ ¡ ¬Ã¨Æ'Å'æ »Ã¨ ¨Ëï ¼Å'æ ´ »Ã¥â° çâŸå žãâ¬âéâ¬â¢Ã§ ¨ ®Ã¨ ½Ã¤ ¼ çšâ Ã¥ ¸Ã§ ¿âæâ¦â¹Ã¥ º ¦Ã¯ ¼Å'æâ" ¢Ã¤ ¸ ç ¬ ¦Ã§ ¾Ã¤ » £Ã¦â¢â¢Ã¨â ²Ã¥Å½Å¸Ã¥â°â¡Ã¯ ¼Å'ä º ¦Ã¦Å"â°Ã© â¢Ã¨â¬Æ'è © ¦Ã¨ââ"é⡠ç â è § £Ã¨Æ' ½Ã¥Å âºÃ¨Ë⡠é â¹Ã§â ¨Ã¦Å â¬Ã¥ · §Ã¤ ¹â¹Ã¦â" ¨Ã£â¬âå⺠æ ¤Ã¯ ¼Å'æÅ" ¬Ã¥ ±â¬Ã§ ± ²Ã¨ «â¹Ã¥ âéâ" ±Ã¥ ·Ã¥â ¡/æâ¢â¢Ã¥ ¸ «Ã©â¬Å¡Ã¥Å âºÃ¥ Ëä ½Å"ï ¼Å'Ã¥ ⦠å ®Ëä ¸Å è ¿ °Ã¥Å½Å¸Ã¥â°â¡Ã£â¬â This marking scheme has been prepared by the Hong Kong Examinations and Assessment Authority for markersââ¬â¢ reference. The Authority has no objection to markers sharing it, after the completion of marking, with colleagues who are teaching the subject. However, under no circumstances should it be givenâ⬠¦show more contentâ⬠¦Because energy loss by the steam is also gained by the surroundings including the air/the jug (usually metallic) that holds milk. 1 ) V 4 4 p1 ( Ã⬠Ãâ" (0.8) 3 ) = (1.01 Ãâ" 10 5 Pa )( Ã⬠Ãâ" (1.0) 3 ) 3 3 p1V1 = p2V2 (Or p Ã¢Ë 5 p1 = 1.97 Ãâ" 10 Pa 1M correct eqn. or with sub. 1A 3 = 45600 J 1 A 1M 1A 2 1A 1A 2 1M 1A correct answer, accept 2 sig. fig. [Accept without 4 Ãâ¬] 3 1A 2 (Accept 1.97 Ãâ" 105 Pa to 2.00 Ãâ" 105 Pa) (b) 3. (a) Volume increases as bubble rises but the speed / k.e. 1A speed / k.e. of molecules of gas molecules remains unchanged unchanged therefore frequency of collision of molecules on 1A frequency of collision on inner bubbleââ¬â¢s inner surface decreases, gas pressure decreases. surface/wall decreases AND pressure decreases 1A (i) 1A Friction f between the tyres and the road. mv 2 f = r 8000 N = (1200 kg)v 2 45 m 1A Friction 1M correct eqn. or with sub. 2 1A 1M 1A correct answer v = 17.3 m s âËâ1 (Accept 17.0 to 17.4 m sââ¬â1) (ii) (b) 1A 3 Smaller For the same f, v2 Ã¢Ë r, r decreases, v decreases. 1A 1A 2 (Max) friction / coefficient of friction reduced, Not enough to provide the centripetal force / acceleration required for circular motion. Or Tracking or allowed speed lowered. 2012-DSE-PHY 1Bââ¬â3 Ã¥ ªÃ©â¢ éâ" ±Ã¥ ·Ã¥â ¡Ã¥ Æ'éâ" ± FOR MARKERSââ¬â¢ USE ONLY 1A 1A 2 Ã¥ ªÃ©â¢ éâ" ±Ã¥ ·Ã¥â ¡Ã¥ Æ'éâ" ± FOR MARKERSââ¬â¢ USE ONLY Marks 4. (a) (i) v = u + at 1M correct sub. into correct eqn. = 60 + (ââ¬â 4)5 1A correct answer = 40 m s ââ¬â1 (ii) 1M 1A 2 v / m s ââ¬â1 60 40 A
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